t^2-5t+6.25=0

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Solution for t^2-5t+6.25=0 equation: 



t^2-5t+6.25=0

a = 1; b = -5; c = +6.25;
Δ = b2-4ac
Δ = -52-4·1·6.25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{5}{2}=2+1/2$

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